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3k^2-9k-84=0
a = 3; b = -9; c = -84;
Δ = b2-4ac
Δ = -92-4·3·(-84)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-33}{2*3}=\frac{-24}{6} =-4 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+33}{2*3}=\frac{42}{6} =7 $
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